A football is thrown horizontally with an initial velocity of (15.7 m/s)x^. Ignoring air resistance, the average acceleration of the football over any period of time is (-9.81 m/s2)y^.
(a) Find the velocity vector of the ball 1.85 s after it is thrown.
v = (_____ m/s)x^ - (______ m/s)y^
(b) Find the magnitude and direction of the velocity at this time.
Direction: _____ degrees below horizontal
I cannot for the life of me figure out this question. Any help would be appreciated! Thank you in advance!
A)as there is no acceleration in horizontal direction horizontal velocity remains same(ie. 15.7m/s) and as there is no initial velocity in vertical direction but acceleration of -9.8
therefore the vector is 15.7x^ -18.13y^
for the direction tanÎ¸ =18.13/15.7
hope u got it